A cow and horse are bought for Rs.2,00,000. The cow is sold at a profit of 20% and the horse is sold a t a loss of 10%. The overall gain is Rs.4000, the Cost price of cow?
a) 130000
b) 80000
c) 70000
d) 120000

• Ans b) 80000
  x+y = 2,00,000
  1.2x+0.9y = 2,04,000
  
  solving these two equation we get x=80,000
• 10 years agoHelpfull: Yes(92) No(4)
• cow=x,horse=y
  x+y=200000
  120*x/100+90*y/100=204000
  on solving tis we get
  x=80000 y=120000
  
• 10 years agoHelpfull: Yes(28) No(1)
• x+y=200000 ------> eqn1 [assume x=cow and y=horse]
  20%x profit-10%y loss=4000
  (20/100)*x-(10/100)*y=4000
  2x-y=40000 --------> eqn2
  by solving eqn1 and eqn2
  we get x=80,000 and y=1,20,000
  ans is 80,000
  
• 10 years agoHelpfull: Yes(15) No(1)
• B) 80000
  20% profit on 80000= 16000/-
  10% loss on 120000=12000/-
  Hence total profit made=16000-12000=4000/-
  Hence cost of cow = 80000/- and cost of horse=120000/-
• 10 years agoHelpfull: Yes(6) No(0)
• C+H=200000
  therefore
  c= 20%C = (120/100)C
  H= -10%H= (90/100)H
  so,
  C+H=2,00,000+40,000=1.2C+09H ... cost price = 80,000
• 10 years agoHelpfull: Yes(6) No(1)
• c+h=2,00,000
  1.2 c + 0.9 h=2,04,000.
  c=80,000.
• 10 years agoHelpfull: Yes(5) No(1)
• 120*x/100+90*y/100=204000
  plz explain this calculation
• 10 years agoHelpfull: Yes(4) No(2)
• it can be solved quickly by hit and trial method if cow prizefrom option=130000,80000,700000,120000 so the corrsponding horse cost respectively 70000,120000,130000,80000 .now applying the cnodition we get cow cost=80000
• 10 years agoHelpfull: Yes(2) No(3)
• cp of cow will be 80000
• 10 years agoHelpfull: Yes(1) No(1)
• c+h=20000
  and c/5-h/10=4000
  by solving these two we get c=80000
  ans is b)80000
• 10 years agoHelpfull: Yes(1) No(1)
• ans. 80,000
• 10 years agoHelpfull: Yes(1) No(2)
• x+y = 2,00,000
  1.2x+0.9y = 2,04,000
  
  so x= 80000.
• 10 years agoHelpfull: Yes(1) No(1)
• Overall profit =
  4000
  200000
  ×
  100
  =
  2
  %
  4000200000×100=2%
  By applying alligation rule, we get
  
  
  So cost price of the cow = 2/5 x 200000 = 80,000
• 6 years agoHelpfull: Yes(1) No(0)
• let c.p of cow be x, c.p of horse is 200000-x
  s.p= {(p+100)*c.p}/100 and s.p={(100-L)*c.p)}/100
  using the formula s.p for cow is 120x/100
  nd for horse is {(200000-x)*90}/100
  find total sp nd subtract it from total cp (given) which is the gain (4000 given) ... you will find x which is the cp of the cow. 80000
• 10 years agoHelpfull: Yes(0) No(0)
• let cow c.p=x
  horse=200000-x
  120/100)*x+(90/100)*(200000-x)=4000
  
• 9 years agoHelpfull: Yes(0) No(0)
• ANS =B
  C+H=2,00,000 RS
  1.2X+0.9Y=2,04,000 RS
  X=80,000 RS
  
• 9 years agoHelpfull: Yes(0) No(0)
• cost of the cow is 80000
  cost of the horse is 120000
  i.e
  c+h=200000
  profit of the cow 20% =120000
  loss of the horse 10%=90000
  overall gain amount is 4000
  120*c/100+90*h/100=204000
• 9 years agoHelpfull: Yes(0) No(2)
• ans:80000
  let horse cost is : h
  then cost of cow=200000-h
  20% profit on cow +10% loss on horse and overall profit=204000
  so
  (90*h)/100 + (200000-h)*(120)/100 = 204000
  after solving
  cost of horse = 120000
  cost of cow = 80000
• 8 years agoHelpfull: Yes(0) No(0)
• THE EQUATION CAN BE WRITTEN AS
  (20/100)*X-(10/100(200000-X))=4000 (LET THE PRICE OF THE COW BE X AND HORSE BE 200000-X)
  X=80000
• 8 years agoHelpfull: Yes(0) No(0)
• .2x-20000+.1x=4000
  x=80000
• 8 years agoHelpfull: Yes(0) No(1)
• b) 80000
  c+h=2,00,000
  1.2c+.9h=2,04,000
  c=80000
• 7 years agoHelpfull: Yes(0) No(0)
• The answer is 80000
• 3 years agoHelpfull: Yes(0) No(0)