TCS
Company
Numerical Ability
Number System
7+77+777+.........7777
total 23 terms 23rd term has 23 7.last 3 digits of result is?
Read Solution (Total 7)
-
- for unit digit
23*7=161,
hence unit digit=1
for 2nd digit
22*7+16=170
hence 2nd digit=0
for 3rd digit
21*7+17=164
hence 3rd digit=4
hence last 3 digit 401 - 10 years agoHelpfull: Yes(24) No(0)
- 7*23=161 1 is last term 16 carry
7*22=154
154+16=170 0 is the second last term 17 carry
7*21=147
147+17=164 so 4 is the third last term
So last three digits are 401 - 10 years agoHelpfull: Yes(9) No(0)
- 21*777=---317
317+77+7=401 - 10 years agoHelpfull: Yes(7) No(0)
- for unit digit =
23*7= 161
hence unit digit =1
carry =16
22*7 + 16 = 170
second digit = 0
carry =17
21*1 +17 =164
third digit = 4 - 10 years agoHelpfull: Yes(1) No(0)
- 401........
- 10 years agoHelpfull: Yes(0) No(0)
- for unit digit
23*7=161,
hence unit digit=1
for 2nd digit
22*7+16=170
hence 2nd digit=0
for 3rd digit
21*7+17=164
hence 3rd digit=4
hence last 3 digit 401 - 10 years agoHelpfull: Yes(0) No(1)
- 401.........
- 9 years agoHelpfull: Yes(0) No(0)
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