44. In the equation A+B+C+D+E=FG, where FG is a two digit number whose value is 10F+G, and letters A, B, C, D, E, F and G each represent different digits. If FG is as large as possible, what is the value of G?

• FG is as large as possible and all the 7 numbers should be different.
  Let’s try out a few possibilities..
  9 + 8 + 7 + 6 + 5 = 35…5 is getting repeated twice.
  9 + 8 + 7 + 6 + 4 = 34…4 is getting repeated
  9 + 8 + 7 + 5 + 4 = 33…3 repeats
  9 + 8 + 6 + 5 + 4 = 32
  None of the numbers repeat in the above case and 32 is the maximum number FG can have. The value of G is 2.
• 11 years agoHelpfull: Yes(68) No(6)
• FG is as large as possible and all the 7 numbers should be different.
  Let’s try out a few possibilities..
  9 + 8 + 7 + 6 + 5 = 35…5 is getting repeated twice.
  9 + 8 + 7 + 6 + 4 = 34…4 is getting repeated
  9 + 8 + 7 + 5 + 4 = 33…3 repeats
  9 + 8 + 6 + 5 + 4 = 32
  None of the numbers repeat in the above case and 32 is the maximum number FG can have. The value of G is 2
• 11 years agoHelpfull: Yes(3) No(1)
• 8 as largest two digit no will be 98 with both the no having unequal digits.
• 11 years agoHelpfull: Yes(1) No(40)
• since a b c d e f are digits max(a,b,c,d,e)=9;
  therefore fg= 5*9=45
  g=5
• 11 years agoHelpfull: Yes(1) No(8)
• 9+8+7+5+4=33
  
  so g=3
  is it correct.......?
  
• 11 years agoHelpfull: Yes(1) No(15)
• FG largest possible if 9+8+7+6+5=35 no
  likewise
  9+8+4+6+5=32 3+2=5
  ans is 5
• 11 years agoHelpfull: Yes(1) No(5)
• value of G is
  G=8
• 11 years agoHelpfull: Yes(0) No(7)
• value of G will be 2.....
• 11 years agoHelpfull: Yes(0) No(0)