Consider a,b,c are three integers whose values are from {1,2,3,4,5}. What is the probability that a*b+c is an even number if a,b,c are selected one after the other after replacement.

• a*b+c
  case 1:(even,odd,even)2*3*2
  case 2:(odd,even,even)2*3*2
  case 3:(even,even,even)2*2*2
  case 4:(odd,odd,odd)3*3*3
  so total cases=59
  req. prob=59/125
• 11 years agoHelpfull: Yes(18) No(0)
• 59/125 is d answer
• 11 years agoHelpfull: Yes(14) No(0)
• 2/5 is d answer...?
• 11 years agoHelpfull: Yes(1) No(1)
• a*b+c= even in cases
  1. a,b,c are odd
  2. a,b,c are even
  
  for case 1.
  3x3x3=27
  for case 2.
  2x2x2=8
  total number of ways for selecting a,b,c with repetition=
  5x5x5=125
  therefore answer could be..
  33/125
• 11 years agoHelpfull: Yes(1) No(9)
• probability = 59/125.
  
  Taking out possible cases/ all cases.
• 11 years agoHelpfull: Yes(1) No(0)
• 59/125 ans
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 17/32
  
• 11 years agoHelpfull: Yes(0) No(6)
• explain answwer
• 11 years agoHelpfull: Yes(0) No(1)