Two years before Paul s age is 2times the Alice age and the present age of Paul is 6times the

paul's age: alice's age=2:1
after some years
paul's age: alice's age=6:1
the question is wrong because a ration of increased inequality cant increase by adding equal number to both
13 years agoHelpfull: Yes(6) No(9)
Let x be Alice's age and y be Paul's current age
y-4 = 3x
y = 6x
so y = 2(y -4) since y =6x and 2(y-4) = 6x also
y = 2y -8
-y = -8
so y =8
Paul is 8 years old
12 years agoHelpfull: Yes(3) No(10)
let present age:
alice=x
paul=y
two yrs ago: 2(x-2)=(y-2)-------(i)
y=6x------(ii)
solving both,we get
x=1/2; y=3
12 years agoHelpfull: Yes(3) No(3)
Let Alice's present age be x
So, Paul's present age is 6x(assume y)
Now, as per given condition,
6x-2=2(x-2)
x=-1/2
y=6*(-1/2)= -3
ignoring negative sign, we can conclude y=3
12 years agoHelpfull: Yes(3) No(2)
let the age of poul=a;
let the age of alice=b;
two year before the condition is
a-2=2(b-2)--------------(1)///poul age was twice of alice
and
now;
a=3b----------------------(2)
by solving two of condition
we get
a=24
b=8
==========SOLVED===========
13 years agoHelpfull: Yes(2) No(14)
p-2=2(a-2)
p=6a
6a-2=2a-4
4a=-2
a=-1/2
p=-3
baby on the womb :)
5 years agoHelpfull: Yes(1) No(0)
let paul's present age be 'x'and alice age be 'y'
two years beflore,
i.e) x-2=2y-----1
at present,
x=6y---------------2
subsitute 2 in 1
6y-2=2y;
4y=2---------3
y=1/2. we want pauls age.subsitute 3 in 2
we will get ,
x=3-----answer is three years
6 years agoHelpfull: Yes(0) No(0)

Two years before Paul’s age is 2times the Alice age and the present age of Paul is 6times the Alice. what is the presents Paul’s age???( 3years) “u try to solve this question once”