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A greengrocer was selling watermelon at a penny each, chickoos at 2 for a penny and peanuts at 3 for a penny. A father spent 7p and got the same amount of each type of fruit for each of his three children, Jane, Joe and Jill. Jane is three years older than Jill and Joe is exactly half the age of Jane and Jill together. What did each child get ?
(a) 1 watermelon, 3 chickoos, 2 peanuts
(b) 1 watermelon, 1 chickoo, 1 peanus
(c) 1 watermelon, 2 chickoos, 2 peanuts
(d) 1 watermelon, 2 chickoos, 1 peanut
Read Solution (Total 6)
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- 1 watermelon costs 1 penny ===> 3 watrmelons for 3 pennies,
2 chickoos cost one peeny ===> 3 kids * 2 chickoos each for 3 pennies
3 peanuts cost one penny ===> 3 peanuts from the balance penny
spending 7 pennies and giving each child 1 watermelon, 2 chickoos and 1 peanut each - 13 years agoHelpfull: Yes(22) No(2)
- age part is of no use
3 watermelon for 3p
6 chickoo for 3p
remaining 1p
so 3peanuts for 1p
all fruits have to b a multiple of 3 as each child will get same amount of each type of fruit - 13 years agoHelpfull: Yes(9) No(1)
- 1 watermelon, 2 chickoos, 1 peanut
- 13 years agoHelpfull: Yes(3) No(2)
- 121........
- 13 years agoHelpfull: Yes(2) No(5)
- always d type ans....either it is a,b,c,or d
- 13 years agoHelpfull: Yes(2) No(0)
- Option d will be the right answer.
Actually father bought all total
3 watermelons cost 3penny
6 chickoos cost 3penny
3 peanuts cost 1penny
then all total 3+3+1 = 7 penny is used for 3 Watermelon,6 chickoos and 2 peanuts
Then distributing equally, each child will get option (d)
- 12 years agoHelpfull: Yes(1) No(1)
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