A pole seen from a certain distance at an angle of 15 degrees and 100 meters ahead by 30 degrees. What is the height of pole ?

• Solution:
  Sol :Here distance by which 30 degree angle is made to look at the pole = X
  Here distance by which 15 degree angle is made to look at the pole = 100+X
  here, Tan 30= H/X ---------(1) //(where H is the height of pole)
  Tan 15= H/(100+X)----------(2)
  Solve for X : (H/Tan 30)=(H/Tan 15)-100 (Tan 30= 0.577, Tan 15= 0.26)
  Answer : 33.33 app.
• 13 years agoHelpfull: Yes(7) No(2)
• ans : h=50m
  
  let height be h
  let dis from 100m to base of pole be x
  
  then,
  tan 15` = h/(100+x) ------ (1)
  tan 30` = h/x ------- (2)
  
  from (2)
  x=h/ tan(30`)
  x= root(3)*h ---- (3)
  
  also,
  tan 15` = sin 30`/ (1+cos 30`)
  tan 15` = 1/(2+root(3))
  
  putting value of tan 15` and (3) in (1)
  
  1/(2+root(3)) = h/(100+root(3)*h)
  1/(2+root(3)) = 1/((100/h)+root(3))
  (100/h)+root(3) = 2+root(3)
  100/h = 2
  h=50m
• 8 years agoHelpfull: Yes(1) No(1)
• height of pole is say H
  tan 15=H/x
  tan 30=H/(x-100)
  so .577=H/((H/.267)-100)
• 13 years agoHelpfull: Yes(0) No(2)