16. In a certain office, 1/3 of the workers are women. 1/2 of the women are married. 1/3 of the married women have children. Similarly, 3/4 of the men are married and 2/3 of the married men have children. What parts of the workers are without children?

• women=p/3(if total no of workers=p) & men=2p/3
  married womn=(p/3)*0.5=p/6 & marrd mn=(2p/3)*(3/4)=p/2
  wmn with chld=(p/6)*(1/3)=p/18 & mn with chld=(p/2)*(2/3)=p/3
  without chld=p-(p/18+p/3)=11p/18
  therefore ans is=11/18
• 11 years agoHelpfull: Yes(47) No(0)
• 11/18
  men- 2/3*(3/4)*(2/3)=(1/3)x
  women - 1/3 *(1/2)* (1/3)=(1/18)x
  add =7x/18
  1-add= soln
• 11 years agoHelpfull: Yes(1) No(0)
• let total num of workers =1
  women workers =13 and men=23
  married workers =13*12=16 and hv child =16*13=118 then women workers have no child= 13-118=518
  similarly for men 23*34*23*=13 have child
  no child for men =23-13=13
  total workers hv no child=13*518=1118
• 11 years agoHelpfull: Yes(0) No(7)
• let say we have 36 of total workers
  
  now 1/3 of 36= women => 12 => male=24
  now 1/2 of 12= married=6 3/4 of 24 = married =18
  now 1/3 of 6= have child =2 2/3 of 18 = have child =12
  
  part of workers without children = 36-(12+2) devided dy 36 => 22/36 = 11/18 As
• 11 years agoHelpfull: Yes(0) No(0)
• total workers=x
  women with children=x/18
  men with children=x/3
  total=x/18+x/3=7x/18
  without children=x-(7x/18)=11x/18
  11/18 part of x are with no children
• 11 years agoHelpfull: Yes(0) No(0)
• 11/18
  women=x/3(if total no of workers=x) & men=2x/3
  married womn=(x/3)*0.5=x/6 & marrd men=(2x/3)*(3/4)=x/2
  wmn with chld=(x/6)*(1/3)=x/18 & men with chld=(x/2)*(2/3)=x/3
  without chld=x-(x/18+x/3)=11x/18
  therefore ans is=11/18
• 11 years agoHelpfull: Yes(0) No(0)