Two towns A and B are 100 km apart A school is to be built for 100 students of town

let the school be at x distance from B.
Then total cost of transportation=(1.20*x*100)+(1.20*(100-x)*30)=3600+84*x.
Now minimum value of x for which transportation cost is minimum=0.
So,school should be at B
10 years agoHelpfull: Yes(17) No(0)
the school should be built at town B.
since 30*1.2*100+100*1.2*0=rs 3600
10 years agoHelpfull: Yes(12) No(4)
dist of A to school: dist of B to school = 30:100= 3:10
A to school: 3/13*100=300/13 kms
B to school 10/13*100=1000/13kms
10 years agoHelpfull: Yes(4) No(8)
school should be at the middle of two town a & b. so distance should be 50 kmfrom a or b
10 years agoHelpfull: Yes(2) No(13)
school should be built at town b
10 years agoHelpfull: Yes(1) No(1)
school should be at B so that expenditure will be mininum and it will be 30*1.2*100=3600 which is minimum.
10 years agoHelpfull: Yes(1) No(1)
school should be at B.
expenditure of each student for 1km of B=100*1.20=120
expenditure of each student for 1km of A=30*1.20=36
total expenditure=120*x+36*y
if x=1 and y=100, total expenditure=3600
hence expenditure will be minimum when the school is build in B.
10 years agoHelpfull: Yes(1) No(1)
ans : 30 km from town A
(30*1.20*100)+(70*1.20*30) is minimum in all possible distances
10 years agoHelpfull: Yes(0) No(8)
70km from A
10 years agoHelpfull: Yes(0) No(3)
23.07 km from point a
10 years agoHelpfull: Yes(0) No(2)
School should be built at town B.
10 years agoHelpfull: Yes(0) No(1)

Two towns A and B are 100 km apart. A school is to be built for 100 students of town B and 30 students of town A. Expenditure on transport is `1.20 per kilometre per student. If the total expenditure on transport by all 130 students is to be as small as possible, then the school should be built at