What is the remainder when 121212......(300 digits) is divided by 99?

• 12/99 gives rem= 12
  1212/99 gives rem= 24 (12*2)
  121212/99 gives rem= 36 (12*3)
  similarly,for 300 digits we have 150 12's
  therefore,12121212....300 digits/99 gives rem =150*12=1800
  Now 1800/99 gives rem =18.
  thus ans=18.
• 10 years agoHelpfull: Yes(52) No(6)
• 18 will be the remainder
• 10 years agoHelpfull: Yes(5) No(0)
• 121212......(300 digits)/(9*11)
  sum of 300 digits=3*150=450
  so given no. is divisible by 9
  thenafter dividend is divided by 11
  remainder must be less than 11
  all the answers are incorrect
  remainer will be 8
  when given no. is divied by 9 dividend will be 13468013468...13468(134680 will be 49 times and last five digit 13468),it will divided by 11,48 times of 134680 will be completely divisible,the last 11 digit 13468013468 wll give the required remainer which is 8
  
• 10 years agoHelpfull: Yes(4) No(1)
• 12/99=remainder (12*1=12)
  1212/99=remainder (12*2=24)
  121212/99=remainder (12*3=36)
  so 121212.....upto 300 times=remainder(12*300=3600)
  3600/99=(99*36)+36
  so remainder is (36)
• 10 years agoHelpfull: Yes(3) No(4)
• when 1800/99 then quotient is 18
  and remainder = 2
  then how u got rem=18..
  plz explain me
• 10 years agoHelpfull: Yes(3) No(1)
• 121/99=1*99+12
  121121/99=1223*99+2*12
  so 12*300/99=72*99+72.....hnce 72 is requried remainder
• 10 years agoHelpfull: Yes(0) No(10)
• reminder will be 8...
• 10 years agoHelpfull: Yes(0) No(7)
• 6 is the remainder.
  121212... when divided by (3*3*11)
  121212....divided by 3 gives 40404... i.e. remainder 0
  divisibility rule of 11 : (sum of digit at even places)- (sum of digits at odd places)= multiple of 11
  thus 4+4+4+...150times=600 , not divisible by 11
  thus 600=594+6. hence making the no 404040.. as ((404040.......46)-6) and hence getting 6 as the remainder.
• 10 years agoHelpfull: Yes(0) No(0)
• 12/99 gives rem= 12
  1212/99 gives rem= 24 (12*2)
  121212/99 gives rem= 36 (12*3)
  similarly,for 300 digits we have 150 12's
  therefore,12121212....300 digits/99 gives rem =150*12=1800
  so ans. is 1800
  
• 10 years agoHelpfull: Yes(0) No(0)
• the remainder will be 8*9=72
  in the last attempt imade it 8
  it willbe 8*9 as already divided by 9
• 10 years agoHelpfull: Yes(0) No(0)
• Reminder is 9
• 10 years agoHelpfull: Yes(0) No(0)
• 1212......300/3*3*11=
  40404.....299/3*11
  so answer is less than 33 which is 18
  
• 10 years agoHelpfull: Yes(0) No(0)
• remainder is 0
• 10 years agoHelpfull: Yes(0) No(0)
• 18
• 10 years agoHelpfull: Yes(0) No(0)