If ABCDEF is a regular hexagon whose area is 42m. Then what is the area of pentagon ABCDE

• regluar hexagon is basically 6 eqilateral trangle
  42/6=7
  now the pentagon which is fomm now is having 5 eqilateral trangle so 7*5=35
  ans=35
• 11 years agoHelpfull: Yes(27) No(0)
• Ans- 35
  
  unbounded ares= (7*2)/2=7
  area pentagon= 42-7=35
• 11 years agoHelpfull: Yes(1) No(0)
• Area(regular hexagon)=6*Area(equilateral tringl)
  => 42 = 6*A(equilateral)
  => A(equilateral) = 42/6 =7
  
  So,Area(pentagon) = 5* A(equilateral) =5*7 =35
  
  you can draw figure and check it out
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• can u elaborate....
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• sourav, a hexagon has 6 triangles so the area of one triangle Is 7 and pentagon has 5 triangles so 7*5=35, is the right answer........
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• are should be in m^2 and 6*7=42 is perimeter not area u guys r solving perimeter is area
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• area of regular polygon = (n*s^2)/4)*cot(180/n)
  
  n= no. of sides of polygon, s= length of side
  
  for hexagon ABCDEF, (6*s^2)/4)*cot(180/6)= 42
  
  we get, s^2/4= 7/root 3
  
  now for pentagon, ABCDE
  area= (5*s^2)/4)*cot(180/5)
  
  =5*(s^2/4)*cot(36)
  =5*7/root 3* cot (36) = 49/root 3
• 10 years agoHelpfull: Yes(0) No(0)