Elitmus
Exam
Numerical Ability
Number System
How many odd factors are there for the value 9,0000000.
Read Solution (Total 14)
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- 90000000= 2^7 *3^2 *5^7 so no. of even factors (2+1)*(7+1)=24
- 11 years agoHelpfull: Yes(38) No(8)
- 9,0000000=3^2*10^7=2^7*3^2*5^7
total factors=(7+1)*(2+1)*(7+1)=8*3*8=192
no. of even factor=(7+1)=8 (only 2^7 gives even factor)
no. of odd factors=(2+1)*(7+1)=24 (3^2*5^7 gives odd factor)
ans 24 - 11 years agoHelpfull: Yes(25) No(1)
- actual question is how many odd factors are there for the value 9,000,000
so we 3x3
(2x5)pow6 so we get
power of 5 is 6 and power of 3 is 2
(6+1)*(2+1)=21
answer is 21 - 11 years agoHelpfull: Yes(20) No(9)
- in question it is 9,00,00,00 = 1,3,9,5,25,125,625,3125,15625,15,75,15,75,375,1875,9375,46875,45,225,1125,5625,28125,140625= 21 factors
and shorcut for it..2^6*3^2*5^6 we cant take 2 and its any power because 2when 2 is multiply with any no its became even therefore 5^6*3^2=(6+1)(2+1)=21 factors - 11 years agoHelpfull: Yes(3) No(2)
- @ankit yar option me 21 tha..
a.5
b.21
c.73
d.76 - 11 years agoHelpfull: Yes(2) No(0)
- ohh ya @akshay kumar singh u r rite actually the value was -9,000,000
- 11 years agoHelpfull: Yes(1) No(2)
- Concept
10=5*2
100=(5^2)*(2^2)
.
.
.
10000000=(5^7)*(2^7)
9*10000000=(3^2)*(5^7)*(2*7)
No. of odd factors in above term are 3^2 and 5^7 so (2+1)*(7+1)=24
- 11 years agoHelpfull: Yes(1) No(0)
- 9,0000000=3^2*10^7=2^7*3^2*5^7
total factors=(7+1)*(2+1)*(7+1)=8*3*8=192
no. of even factor=(7+1)=8 (only 2^7 gives even factor)
no. of odd factors=(2+1)*(7+1)=24 (3^2*5^7 gives odd factor)
ans 24
- 10 years agoHelpfull: Yes(1) No(0)
- @ akshay yr mera bhi answer 21 he aa rha tha but yr 21 is not in option i think so....20 tha shayad in options me..do u remember options???
- 11 years agoHelpfull: Yes(0) No(0)
- @akshay thanks for option hmm shayad main he todha confuse ho rha tha..fir toh maine 21 he lagya hoga..confm
- 11 years agoHelpfull: Yes(0) No(0)
- @ankit-option was-
a> 8
b>21
c>28
the last opt i dont remember..and the correct was b>21.. - 11 years agoHelpfull: Yes(0) No(0)
- 21 is the right answer we can't take 2 , simply because it's a even number and we are told to tell odd factors only.....
- 11 years agoHelpfull: Yes(0) No(0)
- 14 will be the number of odd factors.
- 11 years agoHelpfull: Yes(0) No(0)
- ans will be 3
- 11 years agoHelpfull: Yes(0) No(0)
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