Find the value of (44444445 * 88888885 *
44444442 + 44444438)/(44444444*44444444)

• let 44444444 = x, so 44444445= x+1, 888888885 = 2x-3, 44444442 = x-3
  now, (x+1)*(2x+3)*(x-3)/ x^2
  = 2x-5
  = 88888883
  is the answer
• 11 years agoHelpfull: Yes(60) No(15)
• take x=44444444the eqn becomes
  (x+1)(2x-3)(x-2)+(x-6)/x^2
  
  solving we get 2x-5
  whch is 888888885
• 11 years agoHelpfull: Yes(31) No(14)
• let x=44444444
  ((x+1)(2x-3)(x-2)+(x-6))/x*x
  (x^2(2*x-5))/x^2
  ans = 88888883
• 11 years agoHelpfull: Yes(13) No(1)
• take x=44444444 the eqn becomes
  (x+1)*(2x-3)*(x-2)+(x-6)/x^2
  aftr solving it is (2x-5)= 88888883
  
• 11 years agoHelpfull: Yes(9) No(1)
• take x=44444444
  the eqn becomes
  [(x+1)(2x-3)(x-2)+(x-6)]/x^2
  
  solving we get 2x-5
  which is 888888883
• 11 years agoHelpfull: Yes(4) No(1)
• taking 44444445 =x substituting in given equation
  x*(2x-5)*)(x-3)+(x-7)divided by (x-1)^2
  which gives 2x-7
  put x=44444445 we get ans= 88888883
• 11 years agoHelpfull: Yes(1) No(1)
• 25 is the answer
  
• 11 years agoHelpfull: Yes(0) No(19)
• let 44444445 be x then value is 4x-22
• 11 years agoHelpfull: Yes(0) No(4)
• let 44444444=x
  then 44444445=44444444+1=x+1
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• let 44444444=x
  then 44444445=44444444+1=x+1 and 88888885=88888888-3=2x-3 and 44444442=x-2
  and 44444438=x-6
  so we have to find out the value of
  [(x+1)(2x-3)(x-2)+x-6]/x^2=2x-5=88888888-5=8888883
• 10 years agoHelpfull: Yes(0) No(0)
• let 44444444=x
  (x+1)(2x-3)*(x-2)+(x-6)/(x*x)
  =2x^3-5x^2/(x*x)
  =2x-5
  =88888883(Ans)
  
• 10 years agoHelpfull: Yes(0) No(0)
• let 44444444 = x, so 44444445= x+1, 888888885 = 2x-3, 44444442 = x-3
  now, (x+1)*(2x+3)*(x-3)/ x^2
  = 2x-5
  = 88888883
  
• 10 years agoHelpfull: Yes(0) No(0)
• Let x = 44444444
  (x+1)×(2x−3)×(x−2)+(x−6)/x*x
  (x^2−x−2)×(2x−3)+(x−6)/x*x
  2x^3−2x^2−4x−3x^2+3x+6+x−6/x^2
  2x^3−5x^2/x^2=2x−5
  Substituting the value of x in 2x - 5, we get 88888883
  
• 9 years agoHelpfull: Yes(0) No(0)