In how many ways can we arrange A-Z when A and I can have only 6 letters between them?

• a_ _ _ _ _ _i dis or i_ _ _ _ _ _a= 2
  26-2=24 arranging 6 alphabets out of 24= 24c6*6!
  we have 26-8=18+1=19 packets (18 alphabet + 1 cmbination of a/i _ _ _ _ _ _ i/a)
  dis cud be arrange in 19! ways
  therefore 2*24c6*6!*19! (ans)
• 11 years agoHelpfull: Yes(35) No(1)
• Ans: 24! * 38
  Out of the 26 slots, two
  slots are allocated for A and
  I and can be filled in 2,1
  ways (The first slot can be
  A or I and the second slot
  the remaining).
  The number of ways in
  which A and I can occur in
  different slots = 26-(6+1) =
  19
  Hence total num of ways =
  24! * 2 * 19 = 24! * 38
• 11 years agoHelpfull: Yes(26) No(8)
• A,_,_,_,_,_,_,I...so if we assume this total arrangement as 1 thn it is 26-8+1=19
  so the number of ways is,19!*2!*6!'
  plz let me knw if i am wrong
• 11 years agoHelpfull: Yes(5) No(4)
• 24c6*6!*2!*18!
• 11 years agoHelpfull: Yes(4) No(0)
• no. of positions can be occupied by A & I=2!(1+18)
  arrangement of rest 24 letters is 24!
  so solution is 38*24!
• 11 years agoHelpfull: Yes(2) No(0)
• @VARINDER KUMAR i thnk dat shld be 19! instead of 18!
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 4845456
  
• 11 years agoHelpfull: Yes(0) No(2)
• 24c6*6!*2!*18!
• 11 years agoHelpfull: Yes(0) No(0)
• 19!*2!*6!...
• 11 years agoHelpfull: Yes(0) No(2)
• 19!*6!
  there are 6 no between A and I which can arrange in 6! way ,A and I can arrange in 1 ways.left 18 alpha bates +1=19!ways
  so ans should be 19!*6!.
• 11 years agoHelpfull: Yes(0) No(4)
• guys dont be confused .... 2*24c6*6!*19! == 24! * 38 ...both are correct answer but with different approach
• 11 years agoHelpfull: Yes(0) No(0)
• 24!*39 Ans
• 11 years agoHelpfull: Yes(0) No(0)