in how many ways you can hit a double century only by hitting 4's & 6's.

• The maximum no. of 6 u can hit to get 200 is 32 because 32*6=192 and rest 4*2=8. So for every 2*6=12, it is replaced by 4*3=12. So count goes as 6->32 and 4->2. Next is 6->30 and 4->5. and it goes on till 6->0 and 4->50. Thus the total no. of ways= 0 to 16 = 17 ways..
• 11 years agoHelpfull: Yes(41) No(0)
• 17 ways..
  
• 11 years agoHelpfull: Yes(6) No(3)
• equation will be
  4x+6y = 200
  ==> 2x+3y = 100
  'y' can never be odd and has max limit of 32
  so there are 16 ways
  +
  no '6' condition
  soo total 17 ways..
• 11 years agoHelpfull: Yes(3) No(0)
• 16 ways .
  
• 11 years agoHelpfull: Yes(2) No(6)
• for 20 runs no of ways 4(ie no of 4`s in total-1,i,e (20/4)-1);
  for 50 runs no of ways 11(ie no of 4`s in total-1,i,e (50/4)-1);
  for 200 runs no of ways 49(ie no of 4`s in total-1,i,e (200/4)-1);
• 11 years agoHelpfull: Yes(1) No(5)
• 16 ways...since if he hit 32 6's then 2 4's...30 6's then 5 4's..similarly in this way getting difference of 2...32/2=16 times occur pair of 6's and 4's..so he can make 200 in 16 ways
  
• 11 years agoHelpfull: Yes(1) No(4)
• ya, 1 condition is also there for 0 6's and 50 4's..so 17 ways..i have not mention this condition before..
• 11 years agoHelpfull: Yes(1) No(0)
• 9 ways....
  4x+6y=100
  now put x=1,we get y=16
  likewise total 9 ways
• 11 years agoHelpfull: Yes(0) No(4)
• 17 ways 4x+6y=200
  subsitutng x=2,we get y=32
  likewise 17 ways
• 11 years agoHelpfull: Yes(0) No(2)
• isnt it 9??
  
  those who are saying 17 or 16 plzz explain
• 11 years agoHelpfull: Yes(0) No(1)
• 17ways ..multiples of 6 up to 100 and all 4's
• 11 years agoHelpfull: Yes(0) No(0)
• 17 ways :)
• 11 years agoHelpfull: Yes(0) No(0)