123!
123 last two digits???

• no. of factors of 5 in 123! is given by
  [123/5]+[123/5^2]+[123/5^3] where [] denotes greatest integer function
  =24+4=28
  i.e. 123! contains 5^28
  there are more factors of 2 in 123!(greater than 28)
  so 123! will contain 28 zeroes at the end of 123!
  so last two digit is 00
• 11 years agoHelpfull: Yes(35) No(0)
• 00
  123!=1*2*3*......100*101.....
  since 100 is there so last two digit is 00
  
  
  
  
  
  
  
  =
• 11 years agoHelpfull: Yes(32) No(2)
• 123!=1*2*3*4*...*122*123
  it consists terms 10,20,30,...,100,110 etc
  so last two digit will be 00
• 11 years agoHelpfull: Yes(13) No(0)
• No,,,since in 123!
  1*2*....10*...20*...90*...100*...110*..120*..123 is present.
  So no. of zeros in 123! will be much more in the last.
  So 123 will not be present in last.
  
• 11 years agoHelpfull: Yes(2) No(0)
• ques is 123^123! and ans is x1 nd x can be 0-9
• 11 years agoHelpfull: Yes(2) No(0)
• 123*122*.......100*99....
  hence last digit is00
• 11 years agoHelpfull: Yes(1) No(0)
• 00 as it givess the rem 0
• 11 years agoHelpfull: Yes(0) No(0)
• 00
  bcz 100*x=100x
• 11 years agoHelpfull: Yes(0) No(0)
• 00
• 11 years agoHelpfull: Yes(0) No(0)