From a pack of 52 cards,three cards are drawn at random.Find probability of drawing a king,a queen and jack

• n(S)=52C3
  n(E)=4C1*4C1*4C1=4*4*4=64
  p=n(E)/N(S)=64/52C3
• 11 years agoHelpfull: Yes(33) No(1)
• King=Queen=Jack=4 in every deck.
  (4c1*4c1*4c1 )/ 52c3
  
• 11 years agoHelpfull: Yes(7) No(0)
• Ans - (4/52)*(4/51)*(4/50)
  since the cards are drawn at random..
• 11 years agoHelpfull: Yes(5) No(0)
• King=Queen=Jack=4 in every deck.
  (4c1*4c1*4c1 )/ 52c3 = 64/22100
• 11 years agoHelpfull: Yes(4) No(0)
• sorry there will be 4*4*4/52c3 instead of 53c3...that was written by mistake
  Freinds..
  
• 11 years agoHelpfull: Yes(3) No(0)
• total no of sample space n(s)= 53c3
  now events are n(e)=4c1*4c1*4c1
  so the porbability is p=(4*4*4)/53c3
  so the answer will be= 16/5255
• 11 years agoHelpfull: Yes(2) No(6)
• King=Queen=Jack=4
  (4c1*4c1*4c1 )/ 52c3 = 64/22100
  =16/5525
• 11 years agoHelpfull: Yes(1) No(0)
• In deck of 52 cards queen=king=jack=4.
  probability to drawn card is king = 4C1 = 4
  probability to drawn card is queen = 4C1 = 4
  probability to drawn card is jack = 4C1 = 4
  
  Total number of cases = 52C3
  so probability = 4*4*4 / 52C3
  
  
• 11 years agoHelpfull: Yes(1) No(0)
• 12/1326 as
• 11 years agoHelpfull: Yes(0) No(1)
• solving we get 64/52c3=8/2975
• 11 years agoHelpfull: Yes(0) No(0)
• 8/5525........nt 16/5525
• 11 years agoHelpfull: Yes(0) No(0)