Two goats are tethered to diagonally opposite vertices of a field formed by joining the mid points of adjacent side of another square field of side 20sqrt2. What is total grazing area of two goats?

• The side of the square=20sqrt2 the length of side of of the field=sqrt((10sqrt2)^2+(10sqrt2)^2)=20 so 1 goat will graze =pi.r^2=400pi
  two will graze=2*400pi=800pi
• 11 years agoHelpfull: Yes(8) No(3)
• ans- 400 sq units
• 11 years agoHelpfull: Yes(4) No(10)
• ans- 800sq units
• 11 years agoHelpfull: Yes(3) No(2)
• please explain it....
• 11 years agoHelpfull: Yes(3) No(0)
• ans is 400 sq units
  
• 11 years agoHelpfull: Yes(3) No(0)
• ans-25
  diagonal=2sqrt2*side of a square;
  20sqrt2=2sqrt2* side of a square;
  so,side=10
  side of grazing area=10/2=5;(field is formed by joining the midpoints)
  therefore,grazing area=5*5=25
  
• 11 years agoHelpfull: Yes(0) No(9)
• the tethered goats grazes the grass in semicicle manner (2*half of semicircle).
  so the side is 10/2=5
  and the grazed area is 39.4
• 11 years agoHelpfull: Yes(0) No(4)
• here ...the square field is formed by joining mid points of a square ..of side 20sq 2 ... so ..the field has a side of 10 sq 2 ... so ..
  case 1: from one corner .... take a circle of 5 sq 2 ...the area is 50 pi ...the field is 50 pi /4 ... similatily to case 2 ..results ....25 pi units
  
• 11 years agoHelpfull: Yes(0) No(2)
• side of given square=square root (5).
  we get new square side=square root(5/2)
  so, area=5/2
• 9 years agoHelpfull: Yes(0) No(0)
• diagonal of the inner square would be (10 sqrt 2 )units.
  so the total area grazed by one goat would be (1/2)(pie *(10sqrt2)^2)=100 sq units.
  so by goats it would be 100*2=200 sq units.
• 9 years agoHelpfull: Yes(0) No(0)