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Find the max value of n such that 4257929152626364656667 is perfectly divisible by 42^n.Explanation required.

Read Solution (Total 4)

we have to check only for no. of 7.
here no. of 7's=3
so maxm. value of n=3
11 years agoHelpfull: Yes(21) No(1)

Any number divisible by 42 are only possible when it is divisible by 2,3 and 7.
in given number multiplication of 7 are only 3.
so maximum number of n in 42^n is 3.
11 years agoHelpfull: Yes(12) No(0)
42=2*3*7
only 42,91,63 are divisible by 7 so maximumum no is 3
11 years agoHelpfull: Yes(4) No(0)
check for 7....it is obviously ans is 3
11 years agoHelpfull: Yes(1) No(0)

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