In a mixture of petrol and kerosene, petrol is only 99 litres.If this same quantity of petrol is presented in another mixute of petrol and kerosene where total volume would be 198 litres less than the actual mixture,then the concentration of petrol in the actual mixture would have been 13.33% point less than that of the new mixture.What is the concentration of petrol in actual mixture?

• Ans=20%
  
  (99/(t-198))*100 - (99/t)*100= 13.33
  on solving t=495
  
  so in actual mixture, conc of petrol= 99/495*100= 20%
• 11 years agoHelpfull: Yes(43) No(1)
• Yup!! Absolutely correct!!
• 11 years agoHelpfull: Yes(4) No(2)
• 20%
  [99/(x-198)]*100 - (99/x)*100= 13.33
  solving we get x=495
  so (99/495)*100= 20%
• 11 years agoHelpfull: Yes(3) No(0)
• Kisob problem dichis re? :D :D
• 11 years agoHelpfull: Yes(1) No(0)
• getting a cmplx equation in solving t . did u follow any easy way? @Aarindam
• 11 years agoHelpfull: Yes(0) No(0)
• @suparna guha: I got a quadratic eqn...which turned out to be (t-495)^2
• 11 years agoHelpfull: Yes(0) No(1)