21.if a successively divided by 5,3,2 respectively give the remainder 1,2,0.what is the no when is divided by 2 3, 5?

• when there is successive division.......start calculating the number from reverse
  divided by 2 remainder is 0, number = 2k+0
  now,divided by 3, remainder is 2, number=3(2k)+2
  now divided by 5, remainder is 1, number= 5(3(2k)+2)+1 =5(6k+2)+1 =30k+11
  so,number=30k+11
  by putting k=1, we get number= 41
  
  so,when 41 is sucessively dividded by 2,3,5 remainder will be 1,2,1
  ans is 1,2,1
• 11 years agoHelpfull: Yes(41) No(3)
• The answer is 1,2,1.
  we first assume the no.to be x,and when x is divided by 5,let y be the quotient and 1 is the remainder...
  then when y is divided by 3,let z be the quotient and remainder is 2....
  again when z is divided by 2 the quotient is 1 and leaves 0 as remainder....
  now we can write.
  x=5y+1 . . . (1)
  y=3Z+2. . . .(2)
  z=2*1+0. . ..(3)
  
  from (3) we get z=2,putting z=2 in (2)we get y=8 and similarly x=41...
  now divide 41 by 2,3,5 ....
  and the answer is 1,2,1
  
• 11 years agoHelpfull: Yes(6) No(5)
• same no. when successively divided by 2,3 and 5 we get remainder 1,2,1
• 11 years agoHelpfull: Yes(3) No(3)
• shrt cut way
  5 1
  3 2
  2 0
  0*3+2=2
  2*5+1=11
  now 11/2 thn q=5,r=1
  5/3 thn q=1,r=2
  1/5 thn r=1
  so the ans is 1,2,2
• 11 years agoHelpfull: Yes(2) No(7)
• rem. are 0, 2, 1
• 11 years agoHelpfull: Yes(1) No(14)
• ans=1,2,1
  ..
• 11 years agoHelpfull: Yes(1) No(0)
• 1,2,1 will be the remainders !!!
• 11 years agoHelpfull: Yes(1) No(0)
• Ans will b 41 and it will give rem=1,2,1 resp.
• 11 years agoHelpfull: Yes(0) No(1)
• I think remainder for the last one(2) is 1 not 0, then only the 41 is correct
• 11 years agoHelpfull: Yes(0) No(0)