Capgemini
Company
Numerical Ability
Area and Volume
Q 54. A sphere of 10.5 cm radius is melted and cast into a cuboid of maximum volume. The total surface area of such cuboid is approximately:
A. 1720
B. 1650
C. 1810
D. 1932
Read Solution (Total 6)
-
- volume of sphere=(4/3)*pi*r^3
=(4/3)*pi*(10.5)^3
on solving it comes 11*21*21
let l=11,b=21,h=21
so S=2(lb+bh+hl)
=2(11*21+21*21+21*11)
=2(231+441+231)
=2*903
=1806
so option (C)
- 11 years agoHelpfull: Yes(43) No(18)
- how did you get 11*21*21?
- 10 years agoHelpfull: Yes(16) No(1)
- answer will be A.1720.
volume of sphere=(4/3)*pi*r^3=volume of cube=a^3
so,(4/3)*pi*(10.5)^3=a^3
so,a=16.9
now, surface area of cube=6*a^2=6*(16.9)^2=1720. - 10 years agoHelpfull: Yes(9) No(10)
volume of sphere=(4/3)*pi*r^3
=(4/3)*pi*(10.5)^3
on solving it comes 11*21*21
let l=11,b=21,h=21
so S=2(lb+bh+hl)
=2(11*21+21*21+21*11)
=2(231+441+231)
=2*903
=1806
- 8 years agoHelpfull: Yes(3) No(1)
- Rakesh U r ri8 bro.thanx.
- 10 years agoHelpfull: Yes(1) No(8)
- @Rakesh plz expln why u wrote S=2(lb+bh+bl)
- 7 years agoHelpfull: Yes(0) No(0)
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