CAT
Exam
Numerical Ability
Permutation and Combination
In a chess competition involving some boys and girls of a school, every student had to play exactly one game with every other student. It was found that in 45 games both the players were girls, and in 190 games both were boys. The number of games in which one player was a boy and the other was a girl is
(1) 200
(2) 216
(3) 235
(4) 256
Read Solution (Total 2)
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- Games played among 2 girls out of g girls= 45
» gC2=45 »g(g-1)/2=45 » g(g-1)=90
»»g=10
Games played among 2boys out of b boys= bC2=190
»b(b-1)/2=190 »b=20
Games played involving one girl and one boy= gC1*bC1 =g*b = 10*20=200 - 9 years agoHelpfull: Yes(4) No(0)
- 40+190=235 GAMES
- 10 years agoHelpfull: Yes(0) No(0)
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