Each of the numbers from 1 to 10^6 is repeatedly replaced by its digital sum until we reach 10^6 one digit numbers.Question is will it have more 1's or 2's.

• the question is not at all proper
• 10 years agoHelpfull: Yes(8) No(1)
• 10=1
  11=2
  12=3
  nd so on ans 1's
• 10 years agoHelpfull: Yes(2) No(2)
• chance of getting 1 is 10 only but chance of getting 2 is 11 and 20...so its obvious that probability of getting 2 is higher ..so i think ans will be 2
• 10 years agoHelpfull: Yes(2) No(1)
• ans will be 1:
  from 1 to 10; the numbers are:
  01=0+1=1;2=2;3=3;4=4;5=5;6=6;7=7;8=8;9=9; but
  10=1+0=1
  11=1+1=2
  12=1+2=3
  ...........upto 10^6.
  the number of 1's and 2's are equal but at the end the 10^6=1 gives an extra 1.
  so the answer is 1;
  
  
• 10 years agoHelpfull: Yes(1) No(0)
• 1 will be more as 1 will be present at most of the places at hundredth,thousand as well positions than 2.
• 10 years agoHelpfull: Yes(0) No(0)