Q. Let p and q be two integers such that they have 14 and 384 as their HCF and LCM respectively which of the following will be true?

Option
a) Many such p and q exists
b) Only one such p and q exists
c) No such p and q exists
d) Only two such p and q exists

• We know that, HCF is always a factor of LCM.
  Since 14 is not a factor of 384.
  It follows that there does not exist such p and q.
  Hence the answer is option c.
• 11 years agoHelpfull: Yes(79) No(1)
• Product of two numbers= LCM/HCF
  Let a and b be the two integers and their LCM is L ad HCF is H...
  hence, aXb=L/H . Here pXq= 384/14
  since, this figure is not completely divisible hence, no such p and q exists.
  Ans- C
• 11 years agoHelpfull: Yes(8) No(14)
• many such p and q exists(a)
  
  p*q=14*384
  
  14,384 are not prime numbers....so many such p and q exists
• 11 years agoHelpfull: Yes(6) No(12)
• LCM = 7*2
  HCF = 2^7 * 3
  7 is not the factor of 384.
  Hence their cant be any such integers
  Hence , c
• 11 years agoHelpfull: Yes(5) No(3)
• 14 is not a factor of 384. so, option C
• 10 years agoHelpfull: Yes(1) No(0)
• here option (b) is correct.
• 11 years agoHelpfull: Yes(0) No(4)
• c. hcf value as factor should be there in lcm that is not the case here so the ans is c.
• 4 years agoHelpfull: Yes(0) No(0)