Four men are standing in a market. The average age of all, four years ago was 45 years. Now one man joins them and his age is 49 years. What is the new average age (in years) of all combined together?

• ans =49
  average age = (45*4 +16 +49)5
  =49
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• it is given before 4 years,so present age after 4 years of 4 men is 4*4=16,
  4 years before sum of their age is 45*4,so, ans is (45*4+16+49)/5=49
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• x-4=45
  thus, x=45+4=49
  Thus the average age of 4 person now=49
  present age of the 5th man=49
  thus, average of the total 5 men= (49+49)/2=49 years
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• 49. .ans
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• His age will be 49 years !!!
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• going 4 years back when the average was 45 of four persons. this implies at that time the combined age was 180. now adding 16 years we get the current sum of ages to be 196 and adding 49 of 5th person it becomes 245. hence average now must be 245 divided in 5 which is 49
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• New average age=45+(49-45)/5=45.8
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• (49*4+49)/5=49 ans.
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• avg = 49 years.
  
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• please could u tell me how 16 came into this answer??
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• (45*4+16+49)/5 = 49
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• 49..(45*4+16+49)/5
  
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• 4 yrs ago their avg was 45 yrs.
  Four years hence(i.e now) their avg age=45+4 yrs
  One person whose age is 49 yrs joins them
  Hence avg=49
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• 49
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• ans=49, present tot age=45*4+16=196 so new avg=196+49=245/5=49
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• (45*4+4*16+49)/5=58.6
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• ans 49
  let sum of ages of 4 men 4 years ago be x
  x/4=45
  x=45*4=180
  so present sum of ages=180+(4*4)=196
  now,adding age of man=196+49=245
  so,avg =245/5=49
• 10 years agoHelpfull: Yes(0) No(0)