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Exam
Let the page fault service time be 10ms in a computer with average memory access time being 20ns. If one page fault is generated for every 10^6 memory accesses, what is the effective access time for the memory?
option
(A) 21ns
(B) 30ns
(C) 23ns
(D) 35ns
Read Solution (Total 2)
-
- Answer is A
- 7 years agoHelpfull: Yes(0) No(0)
- solution is B 30ns
formula is:
effective access time for the memory =(page fault rate *page fault service time) +(1- page fault rate)*memory access time
=(1/10^6) * (10*10^-3 *10^9 ns) +[1-(1/10^6) ] * 20 ns
=10 +20 ns
=30ns - 7 years agoHelpfull: Yes(0) No(0)
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