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what is the probability of getting 5 before 7 while 3 dice r thrown?
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- p(5)=6;
p(7)=15;
n(s)=6+15=21;
p=6/21=2/7;
- 11 years agoHelpfull: Yes(25) No(2)
- p(5)/[p(5)+p(7)]=2/7
- 11 years agoHelpfull: Yes(5) No(0)
- let one boy one day work=x
one men one day work=(x+x/2)
atq x+x/2=1/240
x=1/80
then 4 men 9 boy one day work=4*1/160+9*1/240
==1/16
so 16 day is the ans
- 11 years agoHelpfull: Yes(2) No(2)
- total no of events is 216
event of gettin 5 before 7 is 6 i.e.(1,1,3),(1,3,1),(3,1,1),(2,2,1),(2,1,2),(1,2,2)
probability is 6/216 - 11 years agoHelpfull: Yes(1) No(7)
- p(5)=6;
p(7)=12;
n(s)=6+12=18;
p=6/18=1/3; - 11 years agoHelpfull: Yes(1) No(2)
- wht is the formula for finding p(5) or p(7) in these types of questions ??? coz counting doesnt help much if dice no is large say 4 or 5??
- 11 years agoHelpfull: Yes(0) No(0)
- p(5) = 6,
p(7) =15
n(s) = 6+ 15 = 21;
p = 6/21= 2/7 ans. - 11 years agoHelpfull: Yes(0) No(0)
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