An oblong piece of ground measures 19m 2.5dm by 12m 5dm. From the centre of each side a path 2m wide goes across to the centre of the opposite side. Find the cost of paving these paths at the rate of rs.1.32 per sq m?
Option
A Rs. 43.6
B Rs. 78.65
C Rs 54.75
D Rs. 344

• Area of path horizontal=20*192.5=3850 dm^2
  Area of path vertical=20*125=2500 dm^2
  Since center path is covered twice so total area=(3850+2500)-(20*20)=5950 dm^2
  total cost=1.32*59.5 m^2=78.54
• 11 years agoHelpfull: Yes(38) No(1)
• can any one submit the step by step solution with proper explanation
• 10 years agoHelpfull: Yes(6) No(1)
• answer is B.
• 11 years agoHelpfull: Yes(5) No(15)
• 2.5 dm = .0.25m
  19.25 m × 2 m = 38.5 m^2
  12.50 m × 2 m = 25 m^2
  Since they will overlap therefore we have to subtract 2×2 m^2
  Therefore answer will be
  (25 + 38.5 - 4 ) × 1.32
  I.e 78.65
• 7 years agoHelpfull: Yes(5) No(1)
• Can any one submit proper solution to this problem
  i mean step by step solution plz
  
  
• 9 years agoHelpfull: Yes(1) No(2)
• Area of pathway running across the middle of a rectangle = w ( l + b - w )
  = 2 ( 19.25 + 12.5 - 2 )
  = 59.50 sq.m
  Cost for paving 59.50 sq.m = 59.50 * 1.32 = Rs. 78.54
• 6 years agoHelpfull: Yes(1) No(0)
• Please anyone can explain me the whole concept.
• 7 years agoHelpfull: Yes(0) No(0)