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Total income of Eesha in the years 2003,2004,2005 was $36,400.Her income increased by 20% each year.What was her income in 2005?
Read Solution (Total 9)
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- 36400=x+x(1+20/100)+x(1+20/100)^2
36400=364x/100
x=10000
x is salary of year 2003
so salary in year 2005= 10000*(1+20/100)^2
we get $ 14400 - 11 years agoHelpfull: Yes(33) No(3)
- let in 2003 income=x.so in 2004 it will be (x+x*20%)=6x/5.and in 2005 it will be(6x/5+6x/5*20%)=36x/25.
x+6x/5+36x/25=36400 then x=10000.in 2004 income=12000 and in 2005 income=14400 - 11 years agoHelpfull: Yes(24) No(0)
- if the income in 2003 is x
then we have 1.2^2x +1.2x+x=36,400
x=10,000
so 10,000*1.2^2=14,400 - 11 years agoHelpfull: Yes(2) No(0)
- let the income of Eesha in the year 2003 be $X
so, X+(120X/100)+(120/100*120/100X)=36400
after solving u get $14400
- 9 years agoHelpfull: Yes(2) No(0)
- Let the income be Rs x. in the year 2003.
ATQ income increase 20% every year. 20% of x will the income for the year 2004 i.e Rs 6/5 x and for the year 2005 the income will be 20% of Rs 6/5 x i.e. Rs.36/25 x.
total income is Rs 36400.
so
x+6/5x+36/25x=36400
91/25x=36400.
x=10000
income in the year 2005 is 36/25x= 36*400=Rs14400.
- 8 years agoHelpfull: Yes(2) No(0)
- 14400
- 11 years agoHelpfull: Yes(0) No(1)
- Let her income in the year 2003 was x.
so,a.t.q.
36400=x+x(1+20%)+x(1+20%)^2
36400=364x/100
we get,
x=10000
In the year 2005 her income was
10000*(1+20%)^2
we get,
$ 14400.
- 9 years agoHelpfull: Yes(0) No(0)
- income in 2003 is 10000,in 2004 is 12000,in 2005 is 14400
- 8 years agoHelpfull: Yes(0) No(0)
- x+6x/5+36x/25=36400
2003 = $10000
2004= $12000
2005 = $14400 - 6 years agoHelpfull: Yes(0) No(0)
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