A bag contains 5 five rs coins , 8 8 rs coins and 7 7 rs coins .If 4 coins are drawn from the bag at random then find the odds in favor of the draw yeildng the maximum possible amount
option
a) 1:968
b) 968:969
c) 1:909
d) 969:968

• *** wrong question .....
  **corrected one will be :
  Q. . A bag contains 5 five-rupee coins, 8 two-rupee coins and 7 one-rupee coins. If four coins are drawn
  from the bag at random, then find the odds in favour of the draw yielding the maximum possible
  amount.
  a.1:968
  b.968:969
  c.1:969
  d.969:968
• 10 years agoHelpfull: Yes(13) No(0)
• a)1/968 as odds in favour=(5c4/20c4)/(1-(5c4/20c4))
• 10 years agoHelpfull: Yes(10) No(1)
• 8c4/4*4*4*4............
• 10 years agoHelpfull: Yes(0) No(5)
• B) 1:969
  Because
  1-(8/20*7/19*6/18*5/17)
  
• 10 years agoHelpfull: Yes(0) No(4)
• plz elaborate in detail
• 10 years agoHelpfull: Yes(0) No(0)
• 1-(5C4/20C4) = 1- 1/969 = 968/969 so option b
• 10 years agoHelpfull: Yes(0) No(0)
• max amount is 4 8rs. coins so
  8c4/20c4 = 14/969
  odds in favour= num/(denom-num) = 14/(969-14) = 14/955
  answr is not given...
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 14/955......dummy question
• 10 years agoHelpfull: Yes(0) No(3)
• here he mentioned clearly ,if 4 coins are dwn frm bag,
  sototal coins are 20 and mentioned if 4 coins are drwn den we can write it as 20c4 =n(s)
  more over he asked maximum possible amount means its possible with five 5rs coins only(i.e 5c4) but doesnt satisfis with 8rs cions,2rs coins
  ==>so finaly we can write it as 5c4/20c4-1/968
• 10 years agoHelpfull: Yes(0) No(0)