If the height of a tree is 36ft n it breaks at some height and its top touches d other edge of the road..breadth of the road is 12ft..the tree is on d other edge of the road..Find the height at whch the tree broke??

• ht of the tree=36ft
  brdth of rd.=12 ft
  now let the tree break at a height =x ft
  after the tree breaks its touches the other edge of the road and look like a right angle traingle
  so, (36-x)^2 = 12^2 + x^2
  1152=72x
  x=16 ft ans.
• 11 years agoHelpfull: Yes(19) No(3)
• lets us consider the height of the tree from where it break will be x m the the remaining part of the tree which touches the tree will be (36-x)
  Now applying pythagoras theorem (36-x)^2=x^2+144 now solving for x we get x=16m
  so answer is 16 m
• 11 years agoHelpfull: Yes(3) No(0)
• let the 2 sides be a and b
  a+b=36
  a^2+12^2=b^2
  (36-b)^2+144=b^2
  b comes out to be20
  then a=16
  b is the hypotenuse of the so formed right angled triangle
  tree broke 16 ft above the ground
• 11 years agoHelpfull: Yes(1) No(0)
• Ans is 16. let the height if broken tree be h then h^2+12^2=(36-h)^2 from the u can get h
• 11 years agoHelpfull: Yes(1) No(1)
• 16..............
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 16ft
  
• 11 years agoHelpfull: Yes(0) No(2)
• 17.83 apply pythagorus theorem
• 11 years agoHelpfull: Yes(0) No(4)