1^1*2^2*3^3....48^48*49^49 calculate no. Of zeros

• its 250 count number of 5's in 25 its (5*5) so (5^2)^25 gives 5^50 we usually miss there
• 10 years agoHelpfull: Yes(22) No(2)
• count the no. of 5's in 1^1*2^2*3^3....48^48*49^49
  5^5*10^10*15^15*20^20*25^25*30^30*35^35*40^40*45^45(only these terms consists 5)
  =5^5*5^10*5^15*..............*5^45
  so no. of 5's in 1^1*2^2*3^3....48^48*49^49=5+10+15+20+25+..........+45
  =5(1+2+3+........+9)
  =5*45=225
  no. of zZEROES=225
• 10 years agoHelpfull: Yes(9) No(17)
• 250 zeros
  
• 10 years agoHelpfull: Yes(5) No(3)
• count the number of 5s. ans:250
  
• 10 years agoHelpfull: Yes(4) No(3)
• ans is 100
• 10 years agoHelpfull: Yes(1) No(6)
• rakesh kumar ache ladke ho , thora try kro or ye question galat die ho
• 10 years agoHelpfull: Yes(1) No(2)
• number of zero is 100. 10^10,20^20,30^30,40^40 total contain 100 zero.
• 10 years agoHelpfull: Yes(0) No(2)