If 5x 12y 60 then find the minimum value of sqrt x 2 y 2

5x+12y=60
0r (5/13)x + (12/13)y = 60/13
let x=rcosA, y=rsinA so that r=sqrt(x^2 +y^2)
or r(cosA*cosB+sinA.sinB)=60/13 (if 5/13=cosB then sinB=12/13)
or r*cos(A-B)=60/13
or r=(60/13)/cos(A-B)
FOR r=sqrt(x^2 +y^2) to be minm cos(A-B)maxm=1
so minm value of sqrt(x^2+y^2)=60/13
10 years agoHelpfull: Yes(10) No(6)
ANSWER is 4.60
Put x=1 then y=4.5 now value of (x^2+y^2) is (1^2+4.5^2)=(1+20.25)=21.25
now Sqrt(21.25)=4.60 which is minimum among all the values.
So ANSWER is 4.60
10 years agoHelpfull: Yes(9) No(4)
5*0+12*5=60
ans:5
10 years agoHelpfull: Yes(4) No(3)
(5x+12y)^2+(12x−5y)^2=(13^2)*(x^2+y^2).
Since 5x+12y is given, we minimize x^2+y^2 by minimizing (12x−5y)^2. The minimum value of this is 0. It follows that the minimum value of 60/13.
10 years agoHelpfull: Yes(3) No(3)
5x+12y=60
y=5 ans 25
10 years agoHelpfull: Yes(1) No(4)
x=0,y=5
ans is5
10 years agoHelpfull: Yes(0) No(0)

If 5x+12y=60 then find the minimum value of sqrt(x^2+y^2)?