Paul and Jack are friends living in same house. At 12:00 Jack starts to walk from his house at 6kmph. Paul starts at 13:30 to follow Jack from his house on his bicycle at 8kmph. When will Jack be 3 kms behind Paul?(Options r confusing.my ans is 16.30)
option
a)18:30
b)19:00
c)19:30
d)20:00

• ans is c 19:30
  jack after 7.5hr=6*7.5=45km
  paul after 7.5hr but started 1.5hr late, so time will b e reduced by 1.5hr(ie.7.5-1.5=6hr)=8*6=48km
  48-45=3km
• 11 years agoHelpfull: Yes(8) No(0)
• Jake starts at 12.00 and covers 6 km/h Paul starts at 1.30 and covers 8 km/h Relative speed between Jake & paul is 2 kmph, where Paul stating Jake is 9 km ahead of Paul. From 13.30 hours paul takes 4.30 hrs to meet Jake. Again he needs 1.30 hrs to lead Jake by 3 km Relative speed. Totally he takes 6 hrs. so 13.30+6 = 19.30 hrs.
  
• 11 years agoHelpfull: Yes(4) No(0)
• Easiest way is to solve by options.
• 11 years agoHelpfull: Yes(2) No(0)