a bag contain 3 black and 3 white boxes, second bag contains 5 black and 1 white boxes, and finally third bag contains 4 black and 5 white boxes. if a box is chosen at random from one of these bags, the probability that it is not a white box is ?
1) 2/15
2) 11/54
3) 23/54
4) 40/81

• probability of chosing a bag=1/3
  now probability of white box from bag1=3/6
  similarly from bag 2=1/6
  from bag 3=5/9
  so final probablility of not getting a white box=1-p(getting white box)
  =1-[1/3(3/6+1/6+5/9)]
  =16/27
• 10 years agoHelpfull: Yes(18) No(0)
• probability of choosing a bag=P(A1)=P(A2)=P(A3)=1/3
  now probability of choosing a white ball among each bag=P(B/A1)=1/2, P(B/A2)=1/6, P(B/A3)=5/9
  now (A1ᴨB), (A2 ᴨB ) and (A3ᴨB) are mutually exclusive anb
  B=(A1ᴨB)ᴜ(A2ᴨB) ᴜ( A3ᴨB)
  P(B)=P (A1ᴨB)+P(A2ᴨB) +P( A3ᴨB)
  P(B)=P(A1)P(B/A1)+P(A2)P(B/A2)+P(A3)P(B/A3)
  =1/6+1/18+5/27
  =44/108
  Probability of not choosing white ball=1-44/108=16/27
  
  
• 10 years agoHelpfull: Yes(12) No(3)
• ans is 40/81
  
• 10 years agoHelpfull: Yes(5) No(1)
• probability of choosing the bag:1/3
  prob. of getting a black from first bag:1/2
  prob. of getting a black from second bag:5/6
  prob. of getting a black from third bag:4/9
  so total probability:1/3(1/2+5/6+4/9)=16/27
  
• 10 years agoHelpfull: Yes(4) No(0)
• probability of getting white boxes x= 3/6+1/6+1/9 now not getting whit eboxes =1-x
  wher x=yow know!!
• 10 years agoHelpfull: Yes(3) No(7)
• why 1/9?? @tejomay
• 10 years agoHelpfull: Yes(2) No(0)
• bhai sab k sab pagla gye h yaha par tcs ka bhut savaar h inpr
• 10 years agoHelpfull: Yes(1) No(1)
• 11/54.......
• 10 years agoHelpfull: Yes(0) No(3)
• pagla gaye ho sab k sb...ye options me se ans kyo nai aa raha???/
• 10 years agoHelpfull: Yes(0) No(1)
• Choosing a bag will be 1/3
  then white ball from bag one =1/2
  from bag two=1/6
  from bag three=5/9
  
  so overall probability will be
  1-[1/3*(1/2+1/6+5/9)]==16/27
• 9 years agoHelpfull: Yes(0) No(0)