A person meets a train at a railway station coming daily at a particular time. One day he is late by 30 minutes, and he meets the train 5 kms before the station. If his speed is 12 kmph, what is the speed of the train?

• Ans: 60 kph
  
  Suppose Person meets the train everyday at 3 PM at Station A.
  
  His speed is 12kph.
  
  So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.
  
  But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.
  
  Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.
  
  So speed of the train is 5KM/5min = 60 kph.
  
  
• 10 years agoHelpfull: Yes(75) No(2)
• man late by 30 mins
  So distance between man and train = 12/2=6km
  but man meets train 5km before station.
  so 1km of man=5km of train
  12km of man= 60km of train
  ans-60km
  
• 8 years agoHelpfull: Yes(19) No(0)
• nice one!!!
• 10 years agoHelpfull: Yes(10) No(2)
• ans is 60 kmh
  
• 10 years agoHelpfull: Yes(6) No(1)
• The person is 30min late....his speed is 12kmph ..distance from station should be 6kms ( 12kmph * 30 min)....but its 5km in questn...how this is possible?????
• 10 years agoHelpfull: Yes(3) No(3)
• ans is 60 kmph
  
• 10 years agoHelpfull: Yes(3) No(2)
• let train speed = t kmph
  and person covers distance in 1/2 an hour = 12/2=6 km
  so before 1/2 an hour, he was 6 km before station.
  they meet 5km before sation.
  so the distance btwn the man and the train is 6-5=1 km
  so the person goes 1 km in 1/12 hrs.
  now their relative speed, t-12 kmph
  now applying the formula, distance/speed=time, we can equate
  1(distance)/t-12(relative speed) = 1/12(time)
  t=24kmph
  so trains speed = 24kmph
  
  
• 8 years agoHelpfull: Yes(2) No(2)
• is it 30???
• 10 years agoHelpfull: Yes(1) No(5)
• distance /(train -12)-distance/(train-12)=1/2
  now solving this we get speed of train = 22km/hr
  
  
• 9 years agoHelpfull: Yes(1) No(4)
• MADHUSMITA PRADHAN nice approach........shortcut...
  
• 8 years agoHelpfull: Yes(1) No(0)
• Either this question is wrong or all your answers
• 8 years agoHelpfull: Yes(1) No(0)
• it is 60/11 kmph, if its 60 kmph then hw can it travel just 5 km in 25 min??????
  
• 10 years agoHelpfull: Yes(0) No(1)
• let daily he meet at x distance and speed of train is s
  (x-5/s+12)- (x/s+12)= 15/60
  on solving
  s=32
• 9 years agoHelpfull: Yes(0) No(2)
• ans is 60kmph
• 9 years agoHelpfull: Yes(0) No(0)
• Madhusmita pradhan hw u consider 1 km of man = 5 km of train
• 8 years agoHelpfull: Yes(0) No(0)