A greatest 4 digit number when divided by 10, 15, 22 leaves remainder 4, 9, 10. What is the middle two numbers of that number. eg from abcd, what is bc?

• you can solve it through options, and if you divide 9954 by the 10,15,22 they will give remainder as 4,9,10..respectively
  my suggestion will be d'ont break ur head in thinking too much just go through options and get the answer.
  cheers
  all d best
• 10 years agoHelpfull: Yes(24) No(2)
• ans:89
  i think the reminders r 4,9,16 then the
  10-4=6
  15-9=6
  22-16=6
  greatest 4digit no. is 9999
  lcm of 10,14,22 is 330
  9999/330 gives the reminder 99
  9999-99=9900 which is exactly divided by 10,15,22
  when 9900-6=9894.
  therefore the middle two numbers are 89
• 10 years agoHelpfull: Yes(14) No(21)
• its 95
  
  
  
  
  
  
• 10 years agoHelpfull: Yes(12) No(0)
• greatest number is 9954,middle two numbers are 95
• 10 years agoHelpfull: Yes(7) No(0)
• ans - 95
  let take ' N ' is four digit no
  (let a,b,c are quotient)
  so , forming equation , N =10a + 4 --> 4,14,24,34,44,54,64 (lets take a=0,1,2,3,4,5,6,-,-,----
  N =15b + 9 ------> 9,24,39,54,69
  and N =22c + 10 -------> 10,32.54,76
  common term is = 54 (from eqn of all three N)
  general form of N = Lcm (of all dividend no ) * Y + common no
  N = Lcm(10,15,22) * y + 54
  => N = 330y + 54
  now again use hit and trial method for y (for forming four digit no)
  take y=30
  therefore N = 330*30 +54 =9954 (abcd)
  bc=95
• 8 years agoHelpfull: Yes(6) No(0)
• 10-4 , 15-9,22-10 ..and l.c.m of that..so lcm is 12..now devide 9999 by 12.which results 3 as remainder..subtracting that the number comes 9996.so middle two are 99 itself.
• 8 years agoHelpfull: Yes(3) No(1)
• Let N=4-digit no.
  N=10*a+4
  N=15*b+9
  N=22*c+10
  in these 3 equation we have a comman tern,i.e,54
  In this case,General form will be-->N=Lcm(10,15,22)*y+54
  =330*y+54
  =330*30+54
  =9954(abcd)
  so,middle term,i.e,bc=95
• 8 years agoHelpfull: Yes(2) No(0)
• Answer is 80. since he doubled every body else's coind so intially other 3 players would have 16 coins each. So he have to give 16,16,16 coins to everybody i.e 48 and he is also left with 32 coins. So initially he must have 48+32=80 coins
• 10 years agoHelpfull: Yes(0) No(4)
• See rs agarwal boom easiest method at starting of pages
• 6 years agoHelpfull: Yes(0) No(0)