Elitmus
Exam
Numerical Ability
Number System
9. 4 gamblers A, B, C, D are playing with a condition of whoever looses the game doubles all other players money. At the end everybody has 32 coins. then what was
initial coins with A.
Read Solution (Total 8)
-
- a,b,c,d - initial money with abcd
after a loses - a,2b,2c,2d
after b loses - 2a,2b,4c,4d
after c loses - 4a,4b,4c,8d
after d loses - 8a,8b,8c,8d
So, 8a=32, so a=4 - 11 years agoHelpfull: Yes(29) No(6)
- if A is 1st one to loose then ABCD have 66 , 34, 18, 10 respectively. has o be done by backtracking 32 32 32 32 --> 80 16 16 16 --> 40 72 8 8 --> 20 36 68 4 --> 10 18 34 66 --> D C B A
- 11 years agoHelpfull: Yes(11) No(0)
- 1st at last they have 32 coin
then IN last game D would lose then it would have 16 *3 coin + 32=80
in 2nd last C would lose
similarly
making Table
last 32 32 32 32
D 16 16 16 80
C 8 8 72 40
B 4 68 36 20
A 66 34 18 10 - 11 years agoHelpfull: Yes(7) No(0)
- sorry for incomplete question, they loose according to alphebitical order, that 1st A, 2nd B, then C & last D
- 11 years agoHelpfull: Yes(4) No(2)
- 4 coins, not very sure though
as if u take conditions assuming that all have the same no. of coins initially as no case satisfies the given condition if different no. of coins are taken for all, so i assume all take equal no. of coins initially.
Then if initially A,B,C,D have 4 coins each, then when A loses he doubles other, then if B loses he doubles, thn c loses, and then d.
else there can be a condition where A has 32 coins and loses all the game.
so depends on option available.
my ans is 4 or 32
- 11 years agoHelpfull: Yes(1) No(5)
- SMRUTI RANJAN PARDHI when somebody loses we need to distribute his money to other (given in the question)... At the end total money should remain same
- 11 years agoHelpfull: Yes(1) No(1)
- initially let ,
A has x coins, B has y coins, C has z coins, D has w coins,
After D losses, they have 2x, 2y, 2z coins resp. Again when c losses(or any) , they have 4x and 4y coins. again loss, the last one has 8x coins. So, 8x=32 or x =4, or y=8, or z=16 or w=32 - 10 years agoHelpfull: Yes(0) No(0)
- its so simple first take r=1 if r=1 then c =7,3 or l=is 3,7 you can put both the case and take if you check you will get the value of c=7 if c=7 then z=8 you can easily take it and if you put the value of z=8 then you will get the value of b=4 and now you can find the solution easily just put it and check it
- 5 years agoHelpfull: Yes(0) No(0)
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