a b c d e are distinct numbers. if (75-a)(75-b)(75-c)(75-d)(75-e)=2299. then a+B+C+D+E =?

• 2299 can be written as 11*209 = 11*11*19
  
  But we have to select five numbers, so it must be
  (+1) * (-1) * (+11) *(-11) * (19)
  
  S0, it should be
  (75-74) * (75-76) * (75-64) * (75-86) * (75-56)
  a+ b+ c+ d+ e = 74 + 76 + 64 + 86 + 56 = 206
  
  Answer is 206
• 11 years agoHelpfull: Yes(27) No(7)
• 74+76+64+86+56=356 not 206
• 11 years agoHelpfull: Yes(20) No(1)
• 2299=19*11*11*1*1
  a=56, b=64, c=64, d=74, e=74
  a+b+c+d+e=332
• 11 years agoHelpfull: Yes(10) No(7)
• answer should be 356
• 11 years agoHelpfull: Yes(6) No(1)
• @Arira:
  I think your answer is wrong,because it is given that a,b,c,d,e, are distinct numbers
• 11 years agoHelpfull: Yes(4) No(0)
• 2299/11=11*11*19
  75-a=66
  75-a=67
  75-a=68
  75-a=70
  a+b+c+d+e=66+73+68+71+56=334
• 11 years agoHelpfull: Yes(0) No(4)
• I agree with Neha, the answer should be 306.
• 11 years agoHelpfull: Yes(0) No(0)
• 2299=11*11*19*1*1
  >>>> 75-56*75-64*75-64*75-74*75-74=2299
  >>>> 56+64+64+74+74=334ans
• 10 years agoHelpfull: Yes(0) No(0)
• sorry .. twas 74+74+64+64+56=332
• 10 years agoHelpfull: Yes(0) No(0)