if a and b start from their house at 10:00am.they travel from their house to their homeon a road at 20km/h and 40km/h. there is a t junction on the way. a take left at 12 noon from t junction.b reaches the t junction earlier and take right. what is the distance between them at 4:00 pm?

• a travel 4 hr from t junction so 4*20=80km
  b travel 5 hr from t junction so 5*40=200
  so distance between them 80+200=280km
• 11 years agoHelpfull: Yes(42) No(2)
• if they r going in samedirection than diff. will be 200-80=120
• 11 years agoHelpfull: Yes(3) No(0)
• time taken by b to reach the station is not given.
• 11 years agoHelpfull: Yes(2) No(2)
• The distance is 0 km..read the question carefully as they are travelling from home to house which means they have not moved
• 11 years agoHelpfull: Yes(1) No(4)
• a travel 4 hr from t junction so 4*20=80km
  b travel 5 hr from t junction so 5*40=200
  so distance between them 80+200=280km
• 11 years agoHelpfull: Yes(1) No(1)
• sorry..answer is 280 kms
• 11 years agoHelpfull: Yes(1) No(0)
• As a travels towards left at 12 and b travels towards right at 12,
  the distance between a and b is 280-80(the distance which covered between a and b)=200
• 11 years agoHelpfull: Yes(0) No(0)
• distance between them will be 400 kms
• 11 years agoHelpfull: Yes(0) No(4)
• for a
  
  t=2=d/20;
  
  so b take 1 hr to cover 40km at reach t station at 11:00am
  
  a travel 4 hr from t junction so 4*20=80km
  b travel 5 hr from t junction so 5*40=200
  so distance between them 80+200=280km
• 10 years agoHelpfull: Yes(0) No(0)