Q. The Present ages of A & B are in the ratio of 9:7. 13 years ago their ages were in the ratio 25:18. What is the difference of their ages ?

Option
a) 14
b) 16
c) 18
d) 20

• The best way to solve the ages questions is using the ratio given in the problem
  The first ratio is 9:7, so the difference must be a multipleof 2.
  The second ratio is 25: 18, the difference must be a multiple of 7.
  
  So, the difference must be a multiple of 2 and 7, so multiple of 14.
  Choice (1)
• 10 years agoHelpfull: Yes(10) No(1)
• Ans:- 14
  (9x-13)/(7x-13) = 25/18
• 9 years agoHelpfull: Yes(4) No(1)
• x-13/y-13=25/18........1
  x/y=9/7.......................2
  
• 8 years agoHelpfull: Yes(2) No(0)
• (25-18)*13/(25*7-9*18) = 7
  (The ratio of the ages 13yrs ago to the ratio of their present ages, gives the difference when their present ages were in the ratio of 9:7)
  Difference = (9-7)*7 = 14 yrs(The difference obtained in the above step multiplied by the difference of ratios of their present age)
• 9 years agoHelpfull: Yes(0) No(0)