Q. The sum of a two digit number and the number formed by reversing its digits is 110.if the tens digit is 2 more than the units digit. find the number?

Option
a) 64
b) 46
c) 24
d) 42

• (10x+y)+(10y+x)=110
  so that 11x+11y=110
  x+y=10.........(1)
  x=y+2........................(2)
  
  So that x=6,y=4;
  Number =64
  
• 8 years agoHelpfull: Yes(4) No(0)
• Difference of a number and its reverse is always a multiple of 9 and difference of digits.
  Same logic applies when we add a number and its reverse, it will always be 11 times the sum of digits.
  As, the result is 110, the sum of digits is 110/ 11 = 10
  Now the sum of digits is 10 and difference of digits is 2, so the digits are 6 and 4.
  The number is 64.
  
• 10 years agoHelpfull: Yes(3) No(0)
• 10x+y+10y+x=110............(i)
  y=2+x......................(ii)
  solving i & ii
  ans 24
• 9 years agoHelpfull: Yes(0) No(5)
• Two digit number let say (10x+y).
  Now ATP : 10x+y +10y+x = 110;
  11(x+y) = 110.
  Hence, x+y = 10;
  second condition i.e tens digit is 2 more than unit digit. So answer is 46.
• 7 years agoHelpfull: Yes(0) No(5)