f(f(n))+f(n)=2n+3 and f(0)=1. then what is the value of f(2012)?

• ans:2013
  put n=0
  f(f(0))+f(0)=2(0)+3 ............given f(0)=1
  f(1)+1=3
  f(1)=2
  
  now put n=1
  f(f(1))+f(1)=2(1)+3 ......... since we found f(1)=2
  f(2)+2=5
  f(2)=3
  
  similarly.....f(2012)=2013..... answer
• 11 years agoHelpfull: Yes(46) No(0)
• f(0)=1,so f(f(0))+f(0)=3 by putting n=0 so f(1)=2
  now put n=1 then we get f(2)=3 so we can say f(2012)=2013
• 11 years agoHelpfull: Yes(3) No(0)
• f(0) = 1;
  f(f(0)) + f(0) = 2(0) +3
  f(1) + 1 = 3 ( By replacing f(0)=1)
  so, f(1) =2
  
  By applying the same logic,
  f(f(1)) + f(1) = 2(1) + 3
  f(2) + 2 = 5 ( By replacing f(1) = 2)
  So, f(2) = 3
  
  By applying similar logic, f(3) = 4 , f(4)= 5 and so on
  f(2012) = 2013
  Answer is 2013
• 11 years agoHelpfull: Yes(3) No(0)
• f(0)=1
  f(1)=2
  f(2)=3
  like wise f(2012)=2013
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 2013
  
• 11 years agoHelpfull: Yes(0) No(1)
• Put n = 0
  Then f(f(0))+f(0) = 2(0) + 3 ⇒ f(1) + 1 = 3 ⇒ f(1) = 2
  Put n = 1
  f(f(1)) + f(1) = 2(1) + 3 ⇒ f(2) + 2 = 5 ⇒f(2) = 3
  Put n = 2
  f(f(2)) + f(2) = 2(2) + 3 ⇒ f(3) + 3 = 7 ⇒ f(3) = 4
  ......
  f(2012) = 2013
• 11 years agoHelpfull: Yes(0) No(1)
• 2013
  
  i know it will be 2013
• 11 years agoHelpfull: Yes(0) No(0)