Find the greatest number that will divide 43,91,183 so as to leave the same remainder in each case

• Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
  
  = H.C.F. of 48, 92 and 140 = 4.
• 11 years agoHelpfull: Yes(35) No(4)
• ans=4
  remainder is 3
• 11 years agoHelpfull: Yes(3) No(1)
• sqrt(43)=6._
  so we have to divide 43,91,183 with all the no.s below 7.
  ans=4.
• 11 years agoHelpfull: Yes(2) No(2)
• HCF(91-43,183-91)=HCF(48,140)=4
  Hence Ans is 4.
• 9 years agoHelpfull: Yes(1) No(0)
• n*(lcm of 43,91,183 +1)
• 10 years agoHelpfull: Yes(0) No(0)
• number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
  = H.C.F. of 48, 92 and 140 = 4
  
• 9 years agoHelpfull: Yes(0) No(0)