IBM
Company
Numerical Ability
Sequence and Series
What is the next number of the following sequence
22, 19.5, 21.45, 33, 30.5, 33.55, 44, 41.5,......?
Read Solution (Total 11)
-
- 22-2.5=19.5
22-0.55=21.45
and
33-2.5=30.5
33+0.55=33.55
Similarly,
44-2.5=41.5
44-0.55=43.45
The missing term is 43.45 - 11 years agoHelpfull: Yes(48) No(17)
- 1st - 4th = -11
4th - 7th = -11
2nd - 5th = -11
5th - 8th = -11
3rd - 6th = -12.10
6th - 9th = -12.10
so 9th term should be 45.65 - 11 years agoHelpfull: Yes(48) No(14)
- here it is adding or subtracting some values
22-2.5=19.5
22-0.55=21.45
and
33-2.5=30.5
33+0.55=33.55
so,
44-2.5=41.5
44-0.55=43.45
The missing term is 43.45 - 11 years agoHelpfull: Yes(12) No(8)
- there are 3 series... 22,33,44--- cd= 11
19.5,30.5,41.5--- cd=11
and--- 21.45,33.55----- cd=12.1.. so last is== 33.55+12.1=45.65 - 11 years agoHelpfull: Yes(12) No(3)
- 22-19.5=2.5
21.45-19.5=1.95
33-21.45=11.5
33-30.5=2.5
33.55-30.5=3.05
44-33.55=10.45
44-41.5=2.5
now diff of 3.05 & 1.95 is 1.1 add 3.05 with 1.1 result is 4.15 then add 4.15 with the last number in the given sequence i.e 41.5+4.15=45.65
The answer is 45.65 - 11 years agoHelpfull: Yes(9) No(4)
- 22-2.5=19.5
22-0.55=21.45
and
33-2.5=30.5
33+0.55=33.55
Similarly,
44-2.5=41.5
44-0.55=43.45
The answer 43.45 - 11 years agoHelpfull: Yes(6) No(1)
- 45.65..
21.45-19.5=1.95
33.55-30.5=3.05
3.05-1.95=1.1
3.05+1.1=4.15
41.5+4.15=45.65 - 11 years agoHelpfull: Yes(4) No(2)
- 19.5+2.5=22
21.45+0.55=22
&
30.5+2.5=33
33.55-0.55=33
so
41.5+2.5=44
44-0.55=43.45
- 11 years agoHelpfull: Yes(3) No(3)
- 22-33-44 : diff of 11
19.5- 30.5 - 41.5 : diff of 11
21.45 - 33.55 - ? : diff of 12.10..
so answer is : 45.65 - 11 years agoHelpfull: Yes(3) No(2)
- 45.45
22+11=33, 33+11=44
19.5+11=30.5, 30.5+11=41.5
21.45+12=33.45, 33.45+12=45.45 - 11 years agoHelpfull: Yes(2) No(3)
- difffrence between 3rd and 1st,6th and 4th,is -.55and +.55.therefore difffernce between 9th and 7th term would be -.55 and hence answer will be 44-.55=43.45
- 11 years agoHelpfull: Yes(1) No(0)
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