In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid 156 for a journey of 16 km and another person paid 204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is

• Answer is Rs 240
  
  Putting the problem in the form of equation .
  Assume the fixed charge for travel is x and variable to be y
  so for travelling 16 km the total cost is x + 16y = 156 .. equation 1
  and for travelling 24 km the cost is x + 24y = 204 ..... equation 2
  from equation 1 we can derive that x = 156 - 16y ... equation 3
  putting equation 3 in 2 we get
  156 - 16y + 24y = 204 or 8y = 48 or y = 6
  putting y = 6 in eqation 3 we get x = 156-96 or x = 60
  So now the fixed cost is 60 and variable cost is 6
  for traveling 30 kms the cost would be Rs 60 + (30 x 6) = Rs 240
  
  
• 11 years agoHelpfull: Yes(3) No(0)
• let the fixed cost is X.
  the charge per 1km is Y
  then the two eqn are X+16Y=156
  X+24Y=204
  
  solving these 2 eqns we will get y=6
  and X=60
  
  so per 3okm the ans is 240
• 11 years agoHelpfull: Yes(0) No(0)
• 240 = 60+ 30*6
• 10 years agoHelpfull: Yes(0) No(0)
• Shortcut:
  Find the difference between charge and kilometers separately.
  204-156=48 Rupees
  24-16=8 K.m.
  From the above facts, if it is 48 rupees for 8 km.
  Then it will be 36 rupees for 6 km.
  So 204 rupees for 24 km and for additional 6 km it will be 36 rupees.
  sof for 30 k.m. it will be 204+36=240.
  Think logically.
  No need of formulas.
  
• 10 years agoHelpfull: Yes(0) No(0)