If the letters in the word ACTORS are permuted in all possible ways and arranged in alphabetical order.Find the 40th word in permuted alphabetical order.
a.AOSRTC
b.AOTCRS
c.AOSTCR
d.AOSTRC

• answer is AOSRTC,sorry for mistaken before solution I gave.
  first arrange the word in alphabetical order A,C,O,R,S,T.
  arrangement of letter A starting is 120 ways(A|CORST=5! WAYS) so consider next postion AC is arranged in 24 ways(AC|ORST=4! WAYS)therefore the AC starting combinations words are completed with 24th word.
  similarily with A0 combinations the arrangement is completed with 48th word(AOTSRC).we want 40th word so with AOC combination we have 6 words(i.e 24+6=30 positions completed),with AOR combination we have 6 words(i.e 36 postions completed).with AOS combination we have 6 words(i.e 42 words completed) 42nd position is AOSTRC.if we fix AOSC, RT will arranged in 2 ways (i.e 38 postions completed'AOSCTR' IS 38TH WORD).Next fix AOSR, CT will be arranged in 2 ways,1way TC & another way CT.. TC is greater than CT. 39th position is AOSRCT,40th position is AOSRTC.
• 11 years agoHelpfull: Yes(27) No(1)
• Answer is: AOSRTC
  Arranging in alphabetical order as ACORST.
  1.A_ _ _ _ _=5!=120
  2.AC_ _ _ _=4!=24
  3.AOC_ _ _=3!=6
  4.AOR_ _ _=3!=6(36 words).
  5.AOSCRT = 37th word
  6.AOSCTR =38th word
  7.AOSRCT =39th word
  8.AOSRTC =40th word
• 11 years agoHelpfull: Yes(22) No(0)
• is ans is AOSRTC
• 11 years agoHelpfull: Yes(4) No(3)
• ANS IS A.AOSRTC C O R S T
  IF A C ARE FIXED THEN COMBINATION IS 4!= 24
  NOW A O C ARE FIXED THEN COMBINATION IS 3!= 6
  NOW A O R ARE FIXED THEN COMBINATION IS 3!= 6
  NOW A 0 S C ARE FIXED COMBINATION IS 2!=2
  NOW A O S R C T IS 24+6+6+2+1=39 TERM
  SO AOSRTC IS 40 TH WORD
• 11 years agoHelpfull: Yes(4) No(0)
• ANSWER IS (A)AOSRTC
• 11 years agoHelpfull: Yes(3) No(4)
• answer is c) AOSTCR
  = 1*4! + 2*3! + 2*2!
  = 40th word
• 11 years agoHelpfull: Yes(2) No(6)
• AOSRTC is answer.
• 11 years agoHelpfull: Yes(1) No(1)
• AOTCRS
  arrange words in alphabetical order
  first fix A remaining place will be 5!=120 and we need to find 40th word it will definitely come auder 120 so A is fixed at first position.
  similarly try for next alphabets using same criteria we will get the answer.
• 11 years agoHelpfull: Yes(0) No(10)
• The words with
  AC-24
  AOC-6
  AOR-6
  AORC-2
  AORS-2 total there are 40 words in that last word is "AORSTC"
• 11 years agoHelpfull: Yes(0) No(7)
• answer is AOSTCR,
  first arrange the word in alphabetical order A,C,O,R,S,T.
  first arrangement of letter A starting is 120 ways(A|CORST=5! WAYS) so consider next postion AC is arranged in 24 ways(AC|ORST=4! WAYS)therefore the AC starting combinations words are completed with 24th word.
  similarily with A0 combinations the arrangement is completed with 48th word(AOTSRC).we want 40th word so with AOC combination we have 6 words(i.e 30 positions completed),with AOR combination we have 6 words(i.e 36 postions completed).with AOS combination we have 6 words(i.e 42 words completed) 42nd position is AOSTRC. Last 2 positions will be arranged in 2 ways so fix AOST & RC will be arranged as 2! ways 1way RC & another way CR.. RC is greater than CR so 41st position is AOSTRC, 40th position is AOSTCR.
• 11 years agoHelpfull: Yes(0) No(4)
• ACORST-1 st word
  ACTSRO-24
  AOCTSR-30
  AOSRTC-40
• 11 years agoHelpfull: Yes(0) No(0)
• AOSRTC is the right answer
  
• 11 years agoHelpfull: Yes(0) No(0)
• ans is asortc
• 11 years agoHelpfull: Yes(0) No(3)