A person walks at 4 kms/hr for a particular duration T1 and 3km/hr for another duration T2 and covers a total dist of 36km. If he walks at 4km/hr for the duration T2 and at 3km/hr for the duration T1, Then he covers only 34km what will be the time taken by him to cover the one of the legs?

• 36=4t1+3t2
  34=4t2+3t1
  70=7t1+7t2
  t1=6hr t2=4hr
• 10 years agoHelpfull: Yes(18) No(3)
• 4t1+3t2=36
  3t1+4t2=34
  by solving above two equation we get
  t1=6, t2=4
  total time =10hr
• 10 years agoHelpfull: Yes(8) No(1)
• T1+T2=6+4=10
• 10 years agoHelpfull: Yes(7) No(1)
• 4t1+4t2=36
  3t1+4t2=34
  7t1+7t2=70
  t1+t2=10hrs
  
• 10 years agoHelpfull: Yes(4) No(0)
• 4*t1 + 3*t2=36
  3*t1 + 4*t2=34
  by solving above equation
  t1= 6 t2= 4
  so total time = 10 hr
  
  
• 10 years agoHelpfull: Yes(2) No(0)