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Maths Puzzle
Arvind left home at 12.10 p.m. and walked to his grandmother's house. He walked at an average speed of 95 m/min. He arrived at 12:25 p.m. What is the distance between his house and his grandmother's house?
Read Solution (Total 3)
-
- 1 minute-------> 95 meters
15 minutes--------> ?
therefore answer is 1425 meters..or 1.425 km...
- 11 years agoHelpfull: Yes(0) No(0)
- total time=12:25-12:10= 15 minutes
speed=95m/min
so distance=speed*time
=95m/min*15min
=95*15 m
=1425 m
=1.425 km - 11 years agoHelpfull: Yes(0) No(0)
- time 12:25-12:10=00:15
speed=95 m/min
hense distance=15*95
=1425 m - 11 years agoHelpfull: Yes(0) No(0)
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